X^2+100x-2020=0

Solution for X^2+100x-2020=0 equation:

X^2+100X-2020=0

a = 1; b = 100; c = -2020;
Δ = b2-4ac
Δ = 1002-4·1·(-2020)
Δ = 18080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18080}=\sqrt{16*1130}=\sqrt{16}*\sqrt{1130}=4\sqrt{1130}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-4\sqrt{1130}}{2*1}=\frac{-100-4\sqrt{1130}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+4\sqrt{1130}}{2*1}=\frac{-100+4\sqrt{1130}}{2}
$